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Example number 2

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Revision as of 08:28, 28 December 2023 by Elina (talk | contribs) (Created page with "2. (FC3A)16 = (?)8 Solution: (FC3A)16=( )8 First convert hexadecimal to binary (FC3A)16=( )2 ̲ F C 3 A 1111 1100 0011 1010 ∴(FC3A)16=(1111110000111010) 2 1111110000111010 Now convert binary to octal (1111110000111010)2=()8 001 111 110 000 111 010 1 7 6 0 7 2 ∴(1111110000111010)2=( 176072)8 ∴(FC3A)16=( 1760728")
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2. (FC3A)16 = (?)8

Solution: (FC3A)16=( )8

First convert hexadecimal to binary (FC3A)16=( )2 ̲ F C 3 A 1111 1100 0011 1010

∴(FC3A)16=(1111110000111010) 2 1111110000111010

Now convert binary to octal (1111110000111010)2=()8

001 111 110 000 111 010 1 7 6 0 7 2

∴(1111110000111010)2=( 176072)8

∴(FC3A)16=( 1760728

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