Example number 2

2. (FC3A)16 = (?)8

Solution: (FC3A)16=( )8

First convert hexadecimal to binary (FC3A)16=( )2 ̲ F C 3 A 1111 1100 0011 1010

∴(FC3A)16=(1111110000111010) 2 1111110000111010

Now convert binary to octal (1111110000111010)2=()8

001 111 110 000 111 010 1 7 6 0 7 2

∴(1111110000111010)2=( 176072)8

∴(FC3A)16=( 1760728