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Example number 2: Revision history

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28 December 2023

  • curprev 08:2808:28, 28 December 2023‎ Elina talk contribs‎ 341 bytes +341‎ Created page with "2. (FC3A)16 = (?)8 Solution: (FC3A)16=( )8 First convert hexadecimal to binary (FC3A)16=( )2 ̲ F C 3 A 1111 1100 0011 1010 ∴(FC3A)16=(1111110000111010) 2 1111110000111010 Now convert binary to octal (1111110000111010)2=()8 001 111 110 000 111 010 1 7 6 0 7 2 ∴(1111110000111010)2=( 176072)8 ∴(FC3A)16=( 1760728"
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